Section 2
Projections on the Coordinate Axes
The projection of a point on an axis is the place where a perpendicular dropped from the point meets that axis — like the shadow of the point cast straight down (or straight across). Projecting a whole line segment simply means projecting both of its endpoints.
Definition
Projection of a Point
On the x-axis
(x , y) → (x , 0)
Keep the x-coordinate, replace the y-coordinate with 0.
On the y-axis
(x , y) → (0 , y)
Keep the y-coordinate, replace the x-coordinate with 0.
Perpendicular to the x-axis gives A'(3 , 0).
Perpendicular to the y-axis gives A''(0 , 4).
Notice that
- If a point lies on an axis, its projection on that axis is the point itself, and its projection on the other axis is the origin.
- A(3 , 0) lies on the x-axis: its projection on the x-axis is A(3 , 0), and on the y-axis it is O(0 , 0).
- B(0 , -8) lies on the y-axis: its projection on the y-axis is B(0 , -8), and on the x-axis it is O(0 , 0).
Example
Worked Example: Projecting Four Points
Plot A(-2 , 3), B(4 , -1), C(0 , -3), D(2 , 0), then find the projection of each point on both axes.
A(-2 , 3) → x-axis: A'(-2 , 0) · y-axis: A''(0 , 3)
B(4 , -1) → x-axis: B'(4 , 0) · y-axis: B''(0 , -1)
C(0 , -3) → x-axis: O(0 , 0) · y-axis: C(0 , -3) itself
D(2 , 0) → x-axis: D(2 , 0) itself · y-axis: O(0 , 0)
Definition
Projection of a Line Segment
The projection of a line segment on an axis is the projection of every one of its points on that axis. In practice: if A' is the projection of A and B' the projection of B, then A'B' is the projection of AB.
Length of the projection on the x-axis = | x₂ − x₁ | · Length on the y-axis = | y₂ − y₁ |
Rule 1
The projection length is less than or equal to the length of the segment itself.
Rule 2
If the segment is parallel to an axis, its projection on that axis equals its own length.
Rule 3
If the segment is perpendicular to an axis, its projection on that axis is a single point (length 0).
Examples
Worked Examples: Lengths of Projections
Find the length of the projection of AB on the x-axis, where A(2 , 3) and B(-4 , -1).
Project both endpoints onto the x-axis:
A(2 , 3) → A'(2 , 0) , B(-4 , -1) → B'(-4 , 0)
The projection is A'B', so its length is
| -4 | + | 2 | = 6 length units
Equivalently | x₂ − x₁ | = | 2 − (−4) | = 6.
Draw C(1 , 4) and D(5 , 1), then find the length of the projection of CD on the y-axis.
C(1 , 4) → C'(0 , 4) , D(5 , 1) → D'(0 , 1)
Length of C'D' = | 4 | − | 1 | = 3 length units.
Special cases: A(-4 , 3), B(-2 , 3) and then A(5 , 5), B(5 , -1).
AB with A(-4 , 3), B(-2 , 3) is parallel to the x-axis, so its projection there has the same length: | −2 − (−4) | = 2 units.
A₂B₂ with A₂(5 , 5), B₂(5 , -1) is perpendicular to the x-axis, so its projection on the x-axis is the single point (5 , 0) — length 0, while its projection on the y-axis has length | 5 − (−1) | = 6 units.
Your turn
Try It Yourself
- If A(-3 , 2) and B(4 , -4), find the length of the projection of AB on the x-axis and on the y-axis.
- Find the projection length on the x-axis for A(-2 , 1), B(3 , 6) and for A(-3 , 4), B(2 , 2).
- The projection of the point (a + 3 , a − 2) on the x-axis is the point itself. Find the point.
- A point projects to (3 , 0) on the x-axis and to (0 , −2) on the y-axis. What is the point?